Q1. If an aeroplane was to circle around the Earth following parallel 60°N at a ground speed of 480 kt.In order to circle around the Earth along the equator in the same amount of time, it should fly at a ground speed of:
960 kt –
Q2. Consider the following statements on “departure”: *
As the latitude increases, the departure between two meridians decreases –
Q3. An aircraft at latitude 02°20’N tracks 180°(T) for 685 km. On completion of the flight the latitude will be:
03°50’S –
Q4. The suns moves from East to West at a speed of 15° longitude an hour. What ground speed will give you the opportunity to observe the sun due south at all times at 6000N
450 Kt. –
Q5. A is at 5500N 15100W and B at 4500 N 16253W What is the departure? *
458 NM –
Q6. An aircraft departing A(N40° 00′ E080° 00′) flies a constant true track of 270° at a ground speed of 120 kt.What are the coordinates of the position reached in 6 HR?
N40° 00′ E064° 20′ –
Q7. The circumference of the parallel of latitude at 60°N is approximately: *
10 800 NM –
Q8. An aircraft flies the following rhumb line tracks and distances from position 04°00’N 030°00’W : 600 NM South, then 600 NM East, then 600 NM North, then 600 NM West.The final position of the aircraft is:
04°00’N 029°58’W –
Q9. Given: Position ‘A’ is N00° E100°, Position ‘B’ is 240°(T) 200 NM from ‘A’. What is the position of ‘B’?
S01°40′ E097°07′ –
Q10. The circumference of the earth is approximately: *
21600 NM –
Q11. The diameter of the Earth is approximately: *
12 700 km –
Q12. You start from P (7000N 01500E) and fly westward along the parallel of latitude for 2 hours at ground speed 220 Kt.What is your position after two hours flight?
00626W –
Q13. The suns moves from East to West at a speed of 15° longitude an hour. What ground speed will give you the opportunity to observe the sun due south at all times. at 6000N.
450 Kt. –
Q14. What is the time required to travel along the parallel of latitude 60° N between meridians 010° E and 030° W at a groundspeed of 480 kt?
2 HR 30 MIN –
Q15. A flight is to be made from ‘A’ 49°S 180°E/W to ‘B’ 58°S 180°E/W. The distance in kilometers from ‘A’ to ‘B’ is approximately:
1000 –
Q16. What is the longitude of a position 6 NM to the east of 58°42’N 094°00’W?
093°48.5’W –
Q17. The term “departure” used in navigation also have the following meaning *
Distance in direction East/West, given in nautical miles –
Q18. Given: Position ‘A’ N60 W020, Position ‘B’ N60 W021, Position ‘C’ N59 W020.What are, respectively, the distances from A to B and from A to C?
30 NM and 60 NM –