Q1. An aircraft starts from P(50 S 169W) and flies 600 Nm towards West. what’s the current position of the aircraft.
50°00’S 175°27’E – Type: Departure (E/W). Formula: ChLong(min) = Dist / cos(Lat). ChLong = 600 / cos(50) = 933.4 min = 15.56 degrees. Start Long: 169°00’W. Direction: West. New Long: 175°27’E.
Q2. 1…. An aircraft at position 60N 010E travels 1200 NM due South, then travels 1200 NM due East, then 1200 NM due North and then 1200 NM due West. What is the aircraft’s final position?
60°00’N 003°54’W – Leg 1 (S 1200): Arrive 40°N. Leg 2 (E 1200 @40N): dLong = 1200/cos(40) = 1566′ (26.1°E). Leg 3 (N 1200): Arrive 60°N. Leg 4 (W 1200 @60N): dLong = 1200/cos(60) = 2400′ (40.0°W). Net Long: 10E + 26.1 – 40.0 = -3.9 (3°54’W).
Q3. 2….An aircraft at position 30S 120E travels 960 NM due North, then travels 960 NM due East, then 960NM due south and then 960 NM due West. What is the aircraft’s final position?
30°00’S 118°01’E – Leg 1 (N 960): Arrive 14°S. Leg 2 (E 960 @14S): dLong = 960/cos(14) = 989′ (16.48°E). Leg 3 (S 960): Arrive 30°S. Leg 4 (W 960 @30S): dLong = 960/cos(30) = 1108′ (18.47°W). Net Long: 120E + 16.48 – 18.47 = 118.01°E.
Q4. 3….An aircraft at position 30N 160E travels 900 NM due South, then travels 900 NM due East, then 900 NM due North and then 900 NM due West. What is the aircraft’s final position?
30°00’N 158°13’E – Leg 1 (S 900): Arrive 15°N. Leg 2 (E 900 @15N): dLong = 900/cos(15) = 931.7′ (15.53°E). Leg 3 (N 900): Arrive 30°N. Leg 4 (W 900 @30N): dLong = 900/cos(30) = 1039.2′ (17.32°W). Net Long: 160E + 15.53 – 17.32 = 158.21°E (158°13’E).
Q5. 4….An aircraft at position 10S 170W travels 1800 NM due North, then travels 1800 NM due East, then 1800 NM due south and then 1800 NM due West. What is the aircraft’s final position?
10°00’S 168°32’W – Leg 1 (N 1800): Arrive 20°N. Leg 2 (E 1800 @20N): dLong = 1800/cos(20) = 1915′ (31.92°E). Leg 3 (S 1800): Arrive 10°S. Leg 4 (W 1800 @10S): dLong = 1800/cos(10) = 1827′ (30.46°W). Net Long: 170W + 31.92(E) – 30.46(W) = -170 + 1.46 = -168.54 = 168°32’W.
Q6. 5….An aircraft at position 60S 170W travels 1800 NM due East, then travels 1800 NM due North, then 1800 NM due west and then 1800 NM due South. What is the aircraft’s final position?
60°00’S 144°38’W – Leg 1 (E 1800 @60S): dLong = 1800/cos(60) = 3600′ (60.0°E). Leg 2 (N 1800): Arrive 30°S. Leg 3 (W 1800 @30S): dLong = 1800/cos(30) = 2078′ (34.64°W). Net Long: 170W + 60.0(E) – 34.64(W) = -170 + 25.36 = -144.64 = 144°38’W.